Question

The line (p + 2q) x + (p – 3q)y = p – q for different values of p and q passes through the point …

(a) (3/2,5/2)

(b) (2/5,2/5)

(c) (3/5,3/5)

(d) (2/5,3/5)

Answer 1

(d) (2/5,3/5)

(p + 2 q)x + (p – 3q)y = p – q 

px + 2qx + py – 3qy = p – q 

P(x + y) + q (2x – 3y) = p – q 

The fourth option x = 2/5, y = 3/5

= p – q = RHS