\(\begin{bmatrix} 2x + y &4x \\[0.3em] 5x - 7 &4x \end{bmatrix}\)= \(\begin{bmatrix} 7 &7x - 13 \\[0.3em] y &x + 6 \end{bmatrix}\)
⇒ 2x + y = 7 ... (1)
4x = 7y – 13 ... (2)
5x – 7 = y … (3)
4x = x + 6 ... (4)
From (4) 4x – x = 6
3x = 6 ⇒ x = 6/3 = 2
Substituting x = 2 in (1), we get
2(2) + y = 7 ⇒ 4 + y = 7 ⇒ y = 7 – 4 = 3
So x = 2 and y = 3
∴ x + y = 2 + 3 = 5
