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0 votes
1.2k views
in Laws of Motion and Friction by (284 points)
The coins are counted from bottom to top.

1.The force on the 3rd coin due to all coins on its top is equal to 3mg downwards

2.The force on the 6th coin due to 7th coin on its top is equal to 4mg downwards

3.The reaction of the 6th coin on the 7th coin 3mg upwards

4.The total force on 10th coin is 9mg

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1 Answer

+1 vote
by (46.0k points)

2.The force on the 6th coin due to 7th coin on its top is equal to 4mg downwards

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