**x-3/3=y/0=z/-4=$(let) (given)**

**A(3$+3,0,-4$) is any point on given line**

**Dc of y axis 0,1,0**

**Any point on y axis B(0,k,0)**

**DC of AB 3$+3-0,0-k,-4$-0**

**For shortest distance**

**(3$+3)*3+(-k)*0+(-4$)*(-4)=0**

**So,$=-9/25**

**Also,**

**(3$+3)*0+-k*1+(-4$)*0=0**

**So,k=0**

**Therefore shortest distance between the lines is distance between **

**A(48/25,0,-36/25) and B(0,0,0)**

**=12/5**