(b) 8
Given A is a singular matrix ⇒ |A| = 0
(i.e.) \(\begin{bmatrix}e^{x - 2} &e^{7 + x} \\[0.3em]e^{2 + x}&e^{2x + 3}\end{bmatrix}\)= 0
⇒ ex - 2.e2x + 3 – e2 + x.e7 + x = 0
⇒ e3x + 1 – e9 + 2x = 0
⇒ e3x + 1 = e9 + 2x
⇒ 3x + 1 = 9 + 2x
3x – 2x = 9 – 1 ⇒ x = 8