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+1 vote
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in Matrices and Determinants by (47.0k points)
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The value of x, for which the matrix A = \(\begin{bmatrix}e^{x - 2} &e^{7 + x} \\[0.3em]e^{2 + x}&e^{2x + 3}\end{bmatrix}\) is singular is …

(a) 9

(b) 8 

(c) 7 

(d) 6

1 Answer

+1 vote
by (49.2k points)
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Best answer

(b) 8

Given A is a singular matrix ⇒ |A| = 0

(i.e.) \(\begin{bmatrix}e^{x - 2} &e^{7 + x} \\[0.3em]e^{2 + x}&e^{2x + 3}\end{bmatrix}\)= 0

⇒ ex - 2.e2x + 3 – e2 + x.e7 + x = 0 

⇒ e3x + 1 – e9 + 2x = 0 

⇒ e3x + 1 = e9 + 2x 

⇒ 3x + 1 = 9 + 2x 

3x – 2x = 9 – 1 ⇒ x = 8

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