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A block of mass 10 kg is placed on a long trolley. The coefficient of friction between the block and trolley is 0.2. The trolley accelerates from rest with 0.5 m/s2 for 20 s. then what is the friction force?

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Answer: (3) 5N

Mass of the block m=10kg
Acceleration of the trolley a=0.5m/s2

As per newtons second law of motion the force on the block by the motion of the trolley is given by the relation:
F= ma
10×0.5= 5N

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