Fewpal
0 votes
26 views
in Laws of Motion and Friction by (249 points)
closed by

A car is moving along a straight horizontal road with a speed v0​. If the coefficient of friction between the tyres and the road is μ, the shortest distance in which the car be stopped is?

1 Answer

+1 vote
by (52.4k points)
selected by
 
Best answer

Work done against frictional force equals the kinetic energy of the body.
when a body of mass m, moves with velocity v, it has kinetic energy k= 1/2mv2 , this energy is utilized in doing work against the frictional force between the tyres of the car and road.
∴ kinetic energy = work done against friction force 1/2m2 =μ mgs
where s is the distance in which the car is stopped and μ is coefficient of kinetic friction.
Given v=v0 

s=v02/2μg

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...