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A car is moving along a straight horizontal road with a speed v0​. If the coefficient of friction between the tyres and the road is μ, the shortest distance in which the car be stopped is?

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Work done against frictional force equals the kinetic energy of the body.
when a body of mass m, moves with velocity v, it has kinetic energy k= 1/2mv2 , this energy is utilized in doing work against the frictional force between the tyres of the car and road.
∴ kinetic energy = work done against friction force 1/2m2 =μ mgs
where s is the distance in which the car is stopped and μ is coefficient of kinetic friction.
Given v=v0 


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