Given numbers are 8, 9 and 25
Factorization of 8, 9 and 25
8 = 2 × 2 × 2 × 1 = 23 × 1
9 = 3 × 3 × 1 = 32 × 1
25 = 5 × 5 × 1 = 52 × 1
Here, 11 is the smallest power of the common factor 1.
So, HCF (8, 9, 25) = 1
23 × 32 × 52 are the greatest powers of the prime factors 2, 3 and 5 respectively involved in the given three numbers .
LCM of these three integers = 2 × 2 × 2 × 3 × 3 × 5 × 5 = 1800