Given numbers are 42, 63 and 140
Factorization of 42, 63 and 140
Here, 71 is the smallest power of the common factor 7.
So, HCF (42, 63, 140) = 7
22 × 32 × 51 × 71 are the greatest powers of the prime factors 2, 3, 5 and 7 respectively involved in the given three numbers .
LCM of these three integers = 2 × 2 × 3 × 3 × 5 × 7 = 1260