Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
832 views
in Carbonyl Compounds and Carboxylic Acids by (48.6k points)
closed by

An organic compound (A) of molecular formula C2H3OCI on reaction with pd and BaSO4 gives (B) of formula C2H4O. (B) on reaction with LiAIH4 gives (C) of formula C2H6O. (B) on reaction with 12 and NaOH gives (D) of formula CH2ONa and iodoform. identify A,B,C,D and explain the reactions involved.

1 Answer

+1 vote
by (43.8k points)
selected by
 
Best answer

1. From the molecular formula (A) is identified as CH3COCl (Acetyl chloride) 

2. Acetyl chloride on treatment with Pd and BaSO4 gives acetaldehyde CH3CHO as (B)

3. Acetaldehyde on reaction with LiAIH4 gives ethyl alcohol as (C)

4. Acetaldehyde when treated with I and NaOH gives sodium formate (D) and iodoform CHI as products.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...