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An organic compound (A) of molecular formula C2H4 O2 reacts with PCI5 to give (B) of formula C2H3OCI. (B) on treatment with ammonia gives (C) of formula C2H5NO. (C) on reaction with Br2 and KOH gives CH5N as (D). Identify A,B,C,D and explain the reactions involved.

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1. The organic compound (A) is identified as CH3COOH (Acetic acid).

2. Acetic acid reacts with PCI5 to form acetyl chloride as (B)

3. Acetyl chloride on reaction with ammonia gives acetamide as (C)

4. Acetamide on treatment with Br2 , and KOH gives methylamine as (D)

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