Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
3.6k views
in Carbonyl Compounds and Carboxylic Acids by (48.6k points)
closed by

An organic compound (A) of molecular formula C2H5 NO on reaction with P2O5 gives C2H3N(B). (B) on hydrolysis gives (C) of formula C2H4O2 (C) on reaction with LiMB4 gives (D) formula C2H6O. Identify A,B,C,D and explain the reactions involved.

1 Answer

+1 vote
by (43.8k points)
selected by
 
Best answer

1. (A) is identified as CH3CONH2 acetarnide.

2. Acetamide on reaction with P2O5 gives methyl cyanide as (B)

3. Methyl cyanide on acid hydrolysis gives acetic acid CH3COOH as (C)

4. Acetic acid on reaction with LiAlH4 gives ethanol as (D)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...