Let f(x) = 8x2 – 22x – 21
By splitting the middle term, we get
f(x) = 8x2 – 28x + 6x – 21
= 4x(2x – 7) + 3(2x – 7)
= (4x + 3) (2x – 7)
On putting f(x) = 0 , we get
(4x + 3) (2x – 7) = 0
⇒ 4x + 3 = 0 or 2x – 7 = 0
x = -3/4 or x = 7/2
Thus, the zeroes of the given polynomial 8x2 – 22x – 21 are -3/4 and 7/2.
Verification
So, the relationship between the zeroes and the coefficients is verified.