Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
9.3k views
in Polynomials by (55.5k points)
closed by

Find the zeroes of the quadratic polynomials 8x2– 22x – 21 and verify the relationship between the zeroes and the coefficients.

1 Answer

+1 vote
by (50.4k points)
selected by
 
Best answer

Let f(x) = 8x2 – 22x – 21

By splitting the middle term, we get

f(x) = 8x2 – 28x + 6x – 21

= 4x(2x – 7) + 3(2x – 7)

= (4x + 3) (2x – 7)

On putting f(x) = 0 , we get

(4x + 3) (2x – 7) = 0

⇒ 4x + 3 = 0 or 2x – 7 = 0

x = -3/4 or x = 7/2

Thus, the zeroes of the given polynomial 8x2 – 22x – 21 are -3/4 and 7/2.

Verification

So, the relationship between the zeroes and the coefficients is verified.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...