Let f(x) = x2 – (2a + b)x + 2ab
f(x) = x2 – 2ax – bx + 2ab
= x(x – 2a) – b(x – 2a)
= (x – 2a) (x – b)
On putting f(x) = 0 , we get
(x – 2a) (x – b) = 0
⇒ x – 2a = 0 or x – b = 0
⇒x = 2a or x = b
Thus, the zeroes of the given polynomial x2 – (2a + b)x + 2ab are 2a and b
Verification
Sum of zeroes = α + β = 2a + b or
So, the relationship between the zeroes and the coefficients is verified.