Let f(x) = 4 x2 – 4x – 3
By splitting the middle term, we get
f(x) = 4 x2 – 6x + 2x – 3
= 2x(2x – 3) + 1(2x – 3)
= (2x + 1) (2x – 3)
On putting f(x) = 0, we get
(2x + 1) (2x – 3) = 0
⇒ 2x + 1 = 0 or 2x – 3 = 0
x = -1/2 or x = 3/2
Thus, the zeroes of the given polynomial4x2 – 4x – 3 are -1/2 and 3/2.
Verification
So, the relationship between the zeroes and the coefficients is verified.