Given equations are
x + y = 14 …(i)
x – y = 4 …(ii)
From eqn (ii), x = 4 + y …(iii)
On substituting x = 4 + y in eqn (i), we get
⇒ 4 + y + y = 14
⇒ 4 + 2y = 14
⇒ 2y = 14 – 4
⇒ 2y = 10
⇒ y = 10/2 = 5
Now, on putting y = 5 in eqn (iii), we get
⇒ x = 4 + 5
⇒ x = 9
Thus, x = 9 andy = 5 is the required solution.