Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
14.2k views
in Linear Equations by (55.5k points)
closed by

Solve the following pair of linear equations by substitution method:  

x + y = 14; 

x – y = 4

1 Answer

+2 votes
by (50.4k points)
selected by
 
Best answer

Given equations are

x + y = 14 …(i)

x – y = 4 …(ii)

From eqn (ii), x = 4 + y …(iii)

On substituting x = 4 + y in eqn (i), we get

⇒ 4 + y + y = 14

⇒ 4 + 2y = 14

⇒ 2y = 14 – 4

⇒ 2y = 10

⇒ y = 10/2 = 5

Now, on putting y = 5 in eqn (iii), we get

⇒ x = 4 + 5

⇒ x = 9

Thus, x = 9 andimagey = 5 is the required solution.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...