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+1 vote
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in JEE by (30 points)

Two uncharged identical capacitors A and B, each of capacitance C,and an inductor of inductance L are arranged as shown in figure. At t=0, the switch Sis closed while switch S2 remains open. At time t=t0=\( {\sqrt{LC}}\) \( {1\over 2}\), switch S2 is closed while switch S1 is opened. Then, the charge on capacitor A after time tis

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1 Answer

–3 votes
by (43.8k points) 1 flag

Answer is : (c)

by (30 points)
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How is the initial charge on capacitor A 2CE??? Please give the answer in a detailed manner and if possible also mention charge on capacitor B

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