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+2 votes
32.5k views
in Mathematics by (47.0k points)

Let m be the minimum possible value of, log3(3y1 + 3y2 + 3y3) where y1, y2, y3 are real numbers for which y1 + y2 + y3 = 9. Let M be the maximum possible value of (log3x1 + log3x2 + log3x3), where x1, x2, x3 are positive real numbers for which x1 + x2 + x3 = 9. Then the value of log2(m3) + log3(M2) is ______.

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1 Answer

+2 votes
by (49.2k points)

Thus, log2(m3) log3(M2) = 6 + 2 = 8

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