Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
9.8k views
in Circles by (15 points)
edited by

The given figure shows a Pentagon inscribed in a circle with centre O.Given AB=BC=CD and angle ABC=132°

Please log in or register to answer this question.

1 Answer

0 votes
by (46.0k points)

In the figure, O is the centre of circle, with AB = BC = CD.
Also, ∠ABC = 132°

In cyclic quadrilateral ABCE

∠ABC + ∠AEC = 180°     [sum of opposite angles]
→ ∠132 + ∠AEC = 180°
→ ∠AEC = 180° -132°
→ ∠AEC = 48°

Since, AB = BC, ∠AEB = ∠BEC  [equal chords subtends equal angles]

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...