In the figure, O is the centre of circle, with AB = BC = CD.
Also, ∠ABC = 132°
In cyclic quadrilateral ABCE
∠ABC + ∠AEC = 180° [sum of opposite angles]
→ ∠132 + ∠AEC = 180°
→ ∠AEC = 180° -132°
→ ∠AEC = 48°
Since, AB = BC, ∠AEB = ∠BEC [equal chords subtends equal angles]