Let E1 = Manger has some business education and E2 = Manager has some engineering education
P(E1) = 60% = 60/100 = 3/5
and P(E2) = 55% = 55/100 = 11/20
Also, given that 25% managers has some business education but no engineering education.
\(\therefore\) P(E1 - E2) = 25% = 25/100 = 1/4
Now, P(E1) = P(E1 - E2) + P(E1 ∩ E2)
\(\therefore\) P(E1 ∩ E2) = P(E1) - P(E1 - E2)
= 3/5 - 1/4 = (12 - 5)/20 = 7/20.
Now, Probability that a manager has some business education given that he has some engineering education is
P(E1/E2) = P(E1 ∩ E2)/P(E2) = \(\frac{7/20}{11/20}\) = 7/11