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in Linear Equations by (50.4k points)
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Taxi charges in a city consist of fixed charges per day and the remaining depending upon the distance travelled in kilometers. If a person travels 110 km, he pays Rs. 690, and for travelling 200 km, he pays Rs. 1050. Find the fixed charges per day and the rate per km.

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Best answer

Let fixed charge = Rs. x

and charge per kilometer = Rs. y

According to the question,

x + 110y = 690 …(i)

and x + 200y = 1050 …(ii)

On subtracting Eq. (i) from Eq. (ii), we get

x + 200y – x – 110y = 1050 – 690

⇒ 90y = 360

⇒ y = 40

On putting the value of y = 40 in Eq. (i), we get

x + 110(40) = 690

⇒ x + 440 = 690

⇒ x = 690 – 440 = 250

Hence, monthly fixed charges is Rs. 250 and charge per kilometer is Rs. 40

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