Let fixed charge = Rs. x
and charge per kilometer = Rs. y
According to the question,
x + 110y = 690 …(i)
and x + 200y = 1050 …(ii)
On subtracting Eq. (i) from Eq. (ii), we get
x + 200y – x – 110y = 1050 – 690
⇒ 90y = 360
⇒ y = 40
On putting the value of y = 40 in Eq. (i), we get
x + 110(40) = 690
⇒ x + 440 = 690
⇒ x = 690 – 440 = 250
Hence, monthly fixed charges is Rs. 250 and charge per kilometer is Rs. 40