Let the function f be defined f(x) = {(3x, 0 ≤ x ≤ 1),(-3x + 5, 1 < x ≤ 2) then ... (a) limx → 1 f(x) = 1 (b) limx → 1 f(x) = 3 (c) limx → 1 f(x) = 2

Question

Let the function f be defined \(f(x) = \begin{cases} 3x & \quad \text{} 0 ≤ x ≤1\text{ }\\ -3x+5 & \quad \text{} 1<x≤2 \text{ } \end{cases}\) then ...

(a) \(\lim\limits_{x \to 1} f(x)=1\)

(b) \(\lim\limits_{x \to 1} f(x)=3\)

(c) \(\lim\limits_{x \to 1} f(x)=2\)

(d) \(\lim\limits_{x \to 1} f(x)\) does not exist

Answer 1

(d) \(\lim\limits_{x \to 1} f(x)\) does not exist

Limit does not exist