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in Limits and Continuity by (46.9k points)

\(\lim\limits_{x \to 0} \frac{e^{sinx}-1}{x}\) = ...

(a) 1

(b) e

(c) 1/e

(d) 0

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1 Answer

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by (49.1k points)

Answer is (a) 1

\(\lim\limits_{x \to 0} \frac{e^{sinx}-1}{x}\)

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