Let the usual time taken by the aeroplane = x km/hr
Distance to the destination = 1500km
We know that,
Given that speed has to increase by 250 km/hr
⇒ 6(2x – 2x + 1) = 2x2 – x
⇒ 6 = 2x2 – x
⇒ 2x2 –x – 6 = 0
⇒ 2x2 – 4x + 3x – 6 = 0
⇒ 2x (x – 2) + 3 (x – 2) = 0
⇒ (2x + 3) (x – 2) = 0
⇒ (2x + 3) = 0 or (x – 2) = 0
∴ x = 3/2 or x = 2
Since, time can’t be negative.
Hence, the time taken by the aeroplane is 2hrs and the speed is 750km/hr