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In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound. 

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Total mass of organic compound = 0.468 g [Given] 

Mass of barium sulphate formed = 0.668 g [Given] 

1 mol of BaSO4 = 233 g of BaSO4 = 32 g of sulphur 

Thus, 0.668 g of BaSO4 contains (32X0.668/233g) of sulphur = 0.0917 g of sulphur 

Therefore, percentage of sulphur =(0.0197/0.468X100) = 19.59 % 

Hence, the percentage of sulphur in the given compound is 19.59 %. 

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