Given: ∠ABC = 90° and BD⊥ AC
and AB = 5.7 cm, BD = 3.8 cm and CD = 5.4 cm
To find: BC
Firstly, we have to show that △ABC ~△BDC
Let △ABC and △BDC
∠ABC = ∠BDC [each 90°]
∠ACB = ∠BCD [common angle]
∴ △ABC ~ △BDC [by AA similarity criterion]
Since, triangles are similar, hence corresponding sides are proportional.
⇒ BC = 8.1 cm