Given: DE || BC
DE = 5cm, BC = 10cm and area (ΔADE) =20 sq. cm
In ΔABC and ΔADE
∠B = ∠D [∵ DE || BC and AB is transversal, Corresponding angles are equal]
∠C = ∠E [∵ DE || BC and AB is transversal, Corresponding angles are equal]
∠BAC =∠DAE [common angle]
∴ ΔABC ~ ΔADE [by AAA similarity]
Now, we know that the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.