∫(sin^8 x - cos^8 x)/(1 - 2 sin^2 x cos^2 x) dx is ... (a) (1/2) sin 2x + c (b) (-1/2) sin 2x + c (c) (1/2) cos 2x + c (d) (-1/2) cos 2x + c

Question

\(∫\frac{sin^8x-cos^8x}{1-2sin^2x\,cos^2x} dx\) is ...

(a) (1/2) sin 2x + c

(b) (-1/2) sin 2x + c

(c) (1/2) cos 2x + c

(d) (-1/2) cos 2x + c

Answer 1

(b) (-1/2) sin 2x + c

Let