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+1 vote
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in Integral Calculus by (49.2k points)
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\(∫\frac{x\,+\,2}{\sqrt{x^2\,-\,1}}dx\) ... 

(a) √(x2 - 1) - 2 log|x + √(x2 - 1)| + c

(b) sin-1 x - 2 log|x + √(x2 - 1)| + c

(c) 2 log|x + √(x2 - 1)| - sin-1 x + c

(d) √(x2 - 1) + 2 log|x + √(x2 - 1)| + c 

1 Answer

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Best answer

(d) √(x2 - 1) + 2 log|x + √(x2 - 1)| + c 

\(∫\frac{x\,+\,2}{\sqrt{x^2\,-\,1}}dx\)

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