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+1 vote
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in Haloalkanes and Haloarenes by (48.6k points)
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Give reasons for the following: 

1. Ethyl iodide undergoes SN2 reactions faster than ethyl bromide. 

2. (±) 2-Butanol is optically inactive. 

3. C-X bond length in halobenzene is smaller than C-X bond length in CH3 -X.

1 Answer

+1 vote
by (50.9k points)
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Best answer

1. Because in ethyl iodide, iodide being the best leaving group among all the halide ions. Rate of SN2 reaction ability of leaving group.

2. (±) 2-hutanol is a racemic mixture which is optically inactive due to the external compensation. 

3. Due to resonance in halobenzene, it has a smaller bond length value as compared to CH3 - X.

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