Probability of getting admission in IIT = P(A) = 60% = 60/100 = 3/5
Therefore P(A') = 1 - P(A) = 1- 3/5 = 2/5
Probability of getting admission in Anna university = P(B) = 75%
= 75/100 = 3/4
So, P(B') = 1 - 3/4 = 1/4
(i) Probability of getting admission in only one
(ii) Getting admission in atleast one