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in Introduction to Probability Theory by (49.1k points)
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A firm manufactures PVC pipes in three plants viz, X, Y and Z. The daily production volumes from the three firms X, Y and Z are respectively 2000 units, 3000 units and 5000 units. It is known from the past experience that 3% of the output from plant X, 4% from plant Y and 2% from plant Z are defective. A pipe is selected at random from a day’s total production, 

(i) find the probability that the selected pipe is a defective one. 

(ii) if the selected pipe is a defective, then what is the probability that it was produced by plant Y?

1 Answer

+1 vote
by (46.9k points)
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Best answer

Here

(i) P(getting a defective P(pipe) = P(D)

(ii) P(Y/D) 

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