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# If I is the center of a circle inscribed in a triangle ABC, then ∣BC∣IA+∣CA∣IB+∣AB∣IC

by (50.0k points)

We know that the position vector of the incenter of a △ABC is given by

where  $\bar a , \bar b , \bar c$ are the affixes of the vertices of the triangle.
Therefore, in the given triangle ABC, the affix of I is given by

by (245 points)
can u be more precise