A = {2,4,6, 10, 12}
B = {0,1, 2, 4, 5, 9}
f(x) = (x/2) – 1
f(2) = (2/2) – 1 = 1 – 1 = 0
f(4) = (4/2) – 1 = 2 – 1 = 1
f(6) = (6/2) – 1 = 3 – 1 = 2
f(10) = (10/2) – 1 = 5 – 1 = 4
f(12) = (12/2) – 1 = 6 – 1 = 5
(i) Set of ordered pairs
f = {(2, 0) (4, 1) (6, 2) (10, 4) (12, 5}
(ii) Table
x |
2 |
4 |
6 |
10 |
12 |
f(x) |
0 |
1 |
2 |
4 |
5 |
(iii) Arrow diagram
(iv) Graph