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The ordered pairs (a + 1, 4) (3, 4a + b) are equal then (a, b) is … (1) (4, 20) (2) (20, 4) (3) (-4, 20) (4) (20, -4)

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The ordered pairs (a + 1, 4) (3, 4a + b) are equal then (a, b) is …

(1) (4, 20)

(2) (20, 4)

(3) (-4, 20)

(4) (20, -4)

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(3) (-4, 20)

(a + 7, 4) = (3, 4a + b)

a + 7 = 3

a = 3 – 7

= – 4

4a + b = 4

4(-4) + b = 4

-16 + b = 4

b = 4 + 16 = 20

The pair (a, 6) is (-4, 20)

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