Given: Mode = Rs. 24
Frequency (fi) = 100
Class size = 10
Let frequency of the class 10 – 20 be f0. Then, the frequency of the class 30 – 40 will be equal to 100 – 14 – f0 – 27 – 15 = 44 – f0.
It is given that mode = 24, therefore, modal class is 20 – 30.
Thus, lower limit of the modal class (l) = 20
frequency (f0) of class preceding the modal class = f0
frequency (f2) of class succeeding the modal class = 44 – f0
⇒ 4 = 27 - f0
⇒ -23 = -f0
⇒ f0 = 23
∴ f2 = 44 – 23 = 21
Hence, the missing frequencies are 23 and 21.