(a)
- It is co-planar molecule.
- It has six delocalised ir electrons.
- 4n + 2 = 6
4n = 6 – 2
4n = 4
n = 1, obeys Huckel’s rule with n = 1
(b)
1. Molecule is non-planar.
Hence it is a non-aromatic compound.
(c)
- It has a co-planar structure.
- It has two delocalised it electrons.
4n + 2 = 2
4n = 0
n = 0
Hence is an aromatic compound.
