Given, f(x) = 4x2 – 1; x = {-3, -2, -1, 0, 1}
f(x) = 3x – 2; x = {2,3,4}
f(x) = 2x – 3; x = {5,6}
(i) f(5) + f(6)
f(x) = 2x – 3
f(5) = 2(5) – 3 = 10 – 3 = 7
f(6) = 2(6) – 3 = 12 – 3 = 9
∴ f(5) + f(6) = 7 + 9 = 16
(ii) f(1) – f(-3)
f(x) = 4x2 – 1
f(1) = 4(1)2 – 1 = 4 – 1 = 3
f(-3) = [4(-3)2 – 1]
= 4 (9) – 1
= 36 – 1 = 35
∴ f(1) – f(-3) = 3 – (35) = -32
(iii) f(-2) – f(4)
f(x) = 4x2 – 1
f(-2) = 4(-2)2 – 1 = 4(4) – 1 = 16 – 1 = 15
f(x) = 3x – 2
f(4) = [3(4) – 2] = 12 – 2 = 10
∴ f(-2) – f(4) = 15 – 10 = 5
(iv) (f(3) + f(-1))/(2f(6) - f(1))