Given Median =46
Then, median Class = 40 – 50
the lower limit (l) = 40
cumulative frequency of the class preceding 40 – 50 (cf) = 42 + x
frequency of the median class 40 – 50 = 65,
class size (h) = 10
Total frequencies (n) = 229
So, 150 + x + y = 229
⇒ x + y = 229 – 150
⇒ x + y = 79 …(i)
and n/2 = 229/2 = 114.5
Using the formula,
⇒39 = 72.5 – x
⇒ x = 33.5
Putting the value of x in eq. (i), we get
⇒ 33.5 + y = 79
⇒ y = 79 – 33.5
⇒ y = 45.5