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Given f(x) = 5x + 2; g(x) = 2x – 3; h(x) = 3x + 1. Verify fo(goh) = (fog)oh

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f(x) = 5x + 2; g(x) = 2x – 3; h(x) = 3x + 1

L.H.S. = fo(goh)

goh = g[h(x)]

= g(3x + 1)

= 2(3x + 1) – 3

= 6x – 1

fo(goh) = f[goh(x)]

= f(6x – 1)

= 5(6x – 1) + 2

= 30 x – 5 + 2

fo(goh) = 30x – 3 … (1)

R.H.S. = (fog)oh

fog = f[g(x)]

= f(2x – 3)

= 5(2x – 3) + 2

= 30x – 5 + 2

fo(goh) = 30x – 3 …..(1)

R.H.S. = (fog) oh

fog = f[g(x)]

= f(2x – 3)

= 5 (2x – 3)

= 5 (2x – 3) + 2

= 10x – 15 + 2

= 10x – 13

(fog) oh = fog [h(x)]

= fog (3x + 1)

= 10 (3x + 1) – 13

= 30x + 10 – 13

= 30x – 3 … (2)

From (1) and (2) we get L.H.S. = R.H.S.

fo(goh) = (fog)oh

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