Given that f(x) = {(√(x - 1), x ≥ 1), (4, x < 1). Find (i) f(0) (ii) f(3) (iii) f(a + 1) in terms of a. (Given that a > 0)

Question

Given that \( f(x) = \begin{cases} \sqrt{x-1 } & \quad \text{} x≥1 \text{ }\\ 4 & \quad \text{} x <1\text{ } \end{cases}\)

Find

(i) f(0) 

(ii) f(3) 

(iii) f(a + 1) in terms of a. (Given that a > 0)

Answer 1

f(x) = \(\sqrt{x-1}\); f(x) = 4

(i) f(0) = 4

(ii) f(3) = \(\sqrt{3-1}\) = \(\sqrt{2}\)

(iii) f(a + 1) = \(\sqrt{a+1-1}\) = \(\sqrt{a}\)