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For the reaction 2HI(g) ⇌ H2(g) + I2(g) at 720 K, the equilibrium constant value is 50. The equilibrium constant for the reaction H2(g) + I2(g) ⇌ 2HI(g) at the same temperature will be ……

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0.02

Forward reaction equilibrium constant K1 = 50

Reverse reaction equilibrium constant K2 = ? 

K2 = \(\frac{1}{K_1}\) = \(\frac{1}{50}\) = 0.02

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