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The following concentration were obtained for the formation of NH3 from N2 and H2 at equilibrium at 500 K. [N2(g)] = 1.5 x 10^-2 M 

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The following concentration were obtained for the formation of NH3 from N2 and H2 at equilibrium at 500 K.

  • [N2(g)] = 1.5 x 10-2 M 
  • [H2(g)] = 3.0 x 10-2 M 
  • [NH3] = 1.2 x 10-2 M.

N2(g) + 3H2(g) ⇌ 2NH3 (g)

Calculate equilibrium constant.

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N2(g) + 3H2(g) ⇌ 2NH3(g)

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