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Find the 40th term of A.P. whose 9th term is 465 and 20th term is 388.

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Find the 40th term of A.P. whose 9th term is 465 and 20th term is 388.

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tn = a + (n – 1) d 

t9 = a + 8d (t9 = 465)

a + 8d = 465 … (1)

Substitute the value of d = -7 in (1) 

a + 8(-7) = 465 

a – 56 = 465 

a = 465 + 56 = 521 

a = 521, d = -7, n = 40 

t40 = 521 + 39(-7) 

= 521 – 273 = 248 

40th term of an A.P. is 248

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