175 litres of cow’s milk.
105 litres of goat’s milk.
H.C.F of 175 & 105 by using Euclid’s division algorithm.
175 = 105 x 1 + 70, the remainder 70 ≠ 0
Again using division algorithm,
105 = 70 x 1 + 35, the remainder 35 ≠ 0
Again using division algorithm.
70 = 35 x 2 + 0, the remainder is 0.
∴ 35 is the H.C.F of 175 & 105.
(i) ∴ The milk man’s milk can’s capacity is 35 litres.
(ii) No. of cow’s milk obtained = 175/35 = 5 cans
(iii) No. of buffalow’s milk obtained = 105/35 = 3 cans