Mass of KOH = 5.6g
No. of moles = \(\frac{5.6}{5.6}\) = 0.1 mol
1. Volume of the solution = 500 ml = 0.5 L
2. Volume of the solution = 1 L
Molarity = (Number of moles of solute) / (Volume of soluation(in L)
= \(\frac{0.1}{1}\) = 0.1 M
3. Volume of the solution = 1 L Molarity = M
Molarity = \(\frac{0.1}{1}\) M