LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
in Solutions by (46.8k points)
closed by

18 g of glucose is dissolved in 90 g of water. The relative lowering of vapour pressure is equal to ….

1 Answer

+1 vote
by (47.9k points)
selected by
Best answer

Answer: 0.1

\(\frac{P°-P}{P°}\) = x2

x= No. of moles of glucose

\(\frac{18}{180}\) = 0.1

\(\frac{P°-P}{P°}\) = 0.1

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.