# 18 g of glucose is dissolved in 90 g of water. The relative lowering of vapour pressure is equal to ….

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18 g of glucose is dissolved in 90 g of water. The relative lowering of vapour pressure is equal to ….

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$\frac{P°-P}{P°}$ = x2

x= No. of moles of glucose

$\frac{18}{180}$ = 0.1

$\frac{P°-P}{P°}$ = 0.1