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Show that the rate of change of momentum is equal to product of mass and acceleration.

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Let an object of mass ‘m’ is moving along a straight line with initial velocity ‘u’. A constant force ‘F’ is applied in time ‘t’ to accelerate it and its final velocity becomes ‘v’.

Initial momentum, p1 = mu

Final momentum, p2 = mv 

Change in momentum ∝  p2 - p1 ∝ mv – mu
∝m (v – u)

The rate of change of momentum = \(\frac{m(v-u)}{t}\)

Rate of change of momentum = force applied

Force ∝ \(\frac{m(v-u)}{t}\)

Force = k\(\frac{m(v-u)}{t}\)where k = proportionality constant

Force = kma where a = acceleration =\(\frac{m(v-u)}{t}\)

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