Let the first number be ‘X’, so the other number will be ’(X+1)’.
∵ X2 + (X + 1)2 = 421
X2 + X2 + 1 + 2X = 421
On simplifying further,
2X2+ 2X – 420 = 0
X2 + X – 210 = 0
On applying Sreedhracharya formula
∴ X = –15 or X = 14.
∴ X = 14 (Only natural number, as given in the question)
∴ Then other numbers will be 14 & 15.
